NUMS — Medical & Dental Entry Test

NUMS Biology — Cell Structure and Function (Set 5)

Take the NUMS Biology — Cell Structure and Function (Set 5): 30 multiple-choice questions (40 minutes) with instant scoring and a full answer review.…

What this test covers

Sample questions with answers

The first 5 questions of this test, with the correct answer and explanation.

  1. Q1. A spherical cell of radius 5 μm grows to a radius of 15 μm. By what factor does its surface area to volume ratio change?

    • A. It falls to one-ninth
    • B. It falls to one-half
    • C. It rises threefold
    • D. It falls to one-third ✓

    Answer: D. It falls to one-third

    Explanation: SA:V of a sphere = 3/r. Tripling the radius makes the ratio one-third of its original value.

  2. Q2. An electron micrograph is printed so that a mitochondrion of true length 1.5 μm measures 45 mm in the picture. What is the magnification?

    • A. ×300,000
    • B. ×3,000
    • C. ×67,500
    • D. ×30,000 ✓

    Answer: D. ×30,000

    Explanation: 45 mm = 45,000 μm; magnification = image size ÷ actual size = 45,000 ÷ 1.5 = 30,000.

  3. Q3. A scale bar on a micrograph is 20 mm long and is labelled 2 μm. A nucleolus on the same picture measures 35 mm across. What is its real diameter?

    • A. 35 μm
    • B. 3.5 μm ✓
    • C. 7.0 μm
    • D. 1.75 μm

    Answer: B. 3.5 μm

    Explanation: Each 10 mm of picture equals 1 μm, so 35 mm represents 3.5 μm.

  4. Q4. Onion epidermal cells are placed in sucrose solutions. Plasmolysis is seen in 0% of cells at 0.2 M and 0.3 M, 50% at 0.4 M, and 100% at 0.5 M. What is the best conclusion about cells in 0.4 M sucrose?

    • A. Water potential equals the solution's and pressure potential is high
    • B. Water potential equals the solution's and pressure potential is about zero ✓
    • C. Water potential is higher than the solution's and pressure potential is high
    • D. Solute potential is zero and the cells are fully turgid

    Answer: B. Water potential equals the solution's and pressure potential is about zero

    Explanation: The 50% point is incipient plasmolysis: no net water movement, so cell water potential equals that of the solution, and the wall is just no longer pushing back (pressure potential about zero).

  5. Q5. A plant cell has solute potential −0.8 MPa and pressure potential +0.3 MPa. It is placed in a solution of water potential −0.3 MPa. What happens?

    • A. Water leaves the cell, since its water potential is −0.8 MPa
    • B. There is no net movement, since the potentials are equal
    • C. Water enters the cell, since its water potential is −1.1 MPa
    • D. Water enters the cell, since its water potential is −0.5 MPa ✓

    Answer: D. Water enters the cell, since its water potential is −0.5 MPa

    Explanation: Cell ψ = ψs + ψp = −0.8 + 0.3 = −0.5 MPa, lower than the solution's −0.3 MPa, so water moves into the cell.

The other 25 questions

Take the timed test (free, no sign-up) to see your score and the answer and explanation for every question.

  1. Q6. Uptake of a sugar into a cell is measured at increasing external concentrations. The rate rises steeply at first and then levels off at a maximum. Which transport mechanism fits this behaviour best?

    • A. Endocytosis, because the vesicles become saturated
    • B. Osmosis, because the water potential becomes equal
    • C. Facilitated diffusion, because carrier proteins become saturated
    • D. Simple diffusion, because the membrane becomes saturated
  2. Q7. The sodium–potassium pump exports 3 Na⁺ and imports 2 K⁺ for every ATP used. When 15 Na⁺ ions are pumped out, how many K⁺ ions are pumped in?

    • A. 10
    • B. 15
    • C. 5
    • D. 8
  3. Q8. Root hair cells accumulate nitrate against its concentration gradient. When the roots are treated with cyanide, which result would be expected?

    • A. Uptake falls because membrane proteins are digested
    • B. Uptake is unchanged because nitrate moves by osmosis
    • C. Uptake rises because diffusion is no longer opposed
    • D. Uptake falls because less ATP is available for active transport
  4. Q9. In cystic fibrosis, a defective chloride channel in epithelial cells leads to thick, sticky mucus. Which statement best explains the link?

    • A. More chloride leaves cells, so more water follows by osmosis
    • B. More chloride stays in the mucus, so water is drawn back in
    • C. Less chloride enters cells, so more water leaves by osmosis
    • D. Less chloride leaves cells, so less water follows by osmosis
  5. Q10. A baby lacks a lysosomal hydrolase that normally breaks down a membrane lipid, and the lipid builds up in nerve cells. Which statement describes the underlying cause?

    • A. Undigested material accumulates since the lysosome cannot hydrolyse it
    • B. Undigested material accumulates since the Golgi cannot package it
    • C. The lipid is overproduced since the SER makes too much
    • D. The lipid leaks out since the plasma membrane has no proteins
  6. Q11. A cell biologist adds hydrogen peroxide to liver homogenate and observes vigorous bubbling that stops when the homogenate is boiled first. The bubbling comes from

    • A. amylase in the cytosol releasing oxygen
    • B. oxidase in the Golgi releasing hydrogen
    • C. lysozyme in lysosomes releasing carbon dioxide
    • D. catalase in peroxisomes releasing oxygen
  7. Q12. Liver homogenate is spun in stages. A pellet is found to have high succinate dehydrogenase activity but no DNA. The pellet most probably contains

    • A. nuclei
    • B. lysosomes
    • C. ribosomes
    • D. mitochondria
  8. Q13. A drug stops transport vesicles from budding off the rough ER. Newly made secretory proteins would most probably

    • A. accumulate inside the Golgi cisternae
    • B. be released directly from the cell
    • C. accumulate free in the cytosol
    • D. accumulate inside the rough ER
  9. Q14. Chloramphenicol blocks protein synthesis on 70S ribosomes. Which cell components would it be expected to affect in a human cell?

    • A. Nucleolar ribosomal RNA
    • B. Ribosomes on the rough ER
    • C. Free cytoplasmic ribosomes
    • D. Mitochondrial ribosomes
  10. Q15. A cell has a very large, darkly stained nucleolus. What does this indicate about the cell?

    • A. It is making ribosomes and probably synthesising a lot of protein
    • B. It is about to divide, since the nucleolus holds the chromosomes
    • C. It is dying, since the nucleolus fragments in healthy cells
    • D. It is making lipids, since the nucleolus houses the SER
  11. Q16. Which molecules are made in the cytoplasm but must be imported into the nucleus through nuclear pores?

    • A. Ribosomal subunits and tRNA
    • B. Messenger RNA and ribosomal subunits
    • C. Histones and DNA polymerase
    • D. Messenger RNA and transfer RNA
  12. Q17. Colchicine binds tubulin and prevents microtubule assembly. Dividing cells treated with colchicine are most likely to

    • A. arrest in metaphase, with no spindle to pull chromosomes
    • B. arrest in prophase, with no chromosomes condensed
    • C. arrest in cytokinesis, with no actin ring
    • D. continue division, but with unduplicated DNA
  13. Q18. Men with a defect in the dynein arms of the 9+2 axoneme often have chronic respiratory infections and infertility. Which pair of structures fails to move normally?

    • A. Airway cartilage and sperm centrioles
    • B. Airway microvilli and sperm acrosome
    • C. Airway goblet cells and sperm mitochondria
    • D. Airway cilia and sperm flagella
  14. Q19. A pair of centrioles lies near the nucleus of an animal cell. Each centriole is a cylinder of nine microtubule triplets. How many microtubules are in the pair?

    • A. 108
    • B. 27
    • C. 18
    • D. 54
  15. Q20. To obtain individual plant cells from a piece of tissue, a technician uses pectinase. Which structure does this enzyme mainly degrade?

    • A. Plasma membrane
    • B. Middle lamella
    • C. Secondary wall lignin
    • D. Primary wall cellulose
  16. Q21. Heart muscle cells contract almost in unison because an action potential passes quickly from cell to cell. Which junction type makes this possible?

    • A. Desmosomes
    • B. Tight junctions
    • C. Plasmodesmata
    • D. Gap junctions
  17. Q22. Cell P has a cellulose wall, a large central vacuole, chloroplasts and 80S ribosomes. Cell Q has a peptidoglycan wall, 70S ribosomes and a circular chromosome. Which statement is correct?

    • A. P is a plant cell, and Q is a bacterium
    • B. P is a fungus, and Q is a plant cell
    • C. P is a bacterium, and Q is a plant cell
    • D. P is an animal cell, and Q is a bacterium
  18. Q23. A freshwater Paramecium is transferred from pond water to a moderately salty solution. What change is expected in its contractile vacuole?

    • A. It stops forming, because the cell becomes hypertonic to the medium
    • B. It pumps out salt, because the solution is hypotonic to the cell
    • C. It pumps out water more often, because more water enters by osmosis
    • D. It pumps out water less often, because less water enters by osmosis
  19. Q24. Liver cells of patients with high cholesterol levels in blood fail to remove LDL particles because their LDL receptors are absent. Which process is impaired?

    • A. Facilitated diffusion of cholesterol
    • B. Exocytosis of secretory vesicles
    • C. Receptor-mediated endocytosis
    • D. Pinocytosis through random pits
  20. Q25. A pancreatic acinar cell secretes enzymes constantly, and its plasma membrane area stays nearly constant. What explains this?

    • A. Membrane added by exocytosis is retrieved by endocytosis
    • B. Membrane added by endocytosis is released by exocytosis
    • C. Membrane added by exocytosis is broken down by lysosomes
    • D. Membrane is made faster by free ribosomes in the cytosol
  21. Q26. Cold-adapted fish have more unsaturated phospholipids in their membranes than tropical fish. What is the advantage?

    • A. It lets cholesterol leave the membrane at low temperature
    • B. It makes the membrane rigid at low temperature
    • C. It keeps the membrane fluid at low temperature
    • D. It stops water crossing the bilayer at low temperature
  22. Q27. Blood group A and blood group B red cells differ only in the sugar chains carried on the outer face of their membranes. Which feature is described?

    • A. Integral channel proteins that move sugars across the membrane
    • B. Cholesterol molecules that fix membrane fluidity
    • C. Peripheral proteins that anchor the cytoskeleton inside the cell
    • D. Glycocalyx glycoproteins and glycolipids used for cell recognition
  23. Q28. A potato tuber stored in light slowly turns green near the surface. Which change in its plastids explains this?

    • A. Elaioplasts convert to chromoplasts
    • B. Chromoplasts convert to amyloplasts
    • C. Chloroplasts convert to leucoplasts
    • D. Amyloplasts convert to chloroplasts
  24. Q29. A red blood cell and a plant cell are both placed in distilled water. The red cell bursts, but the plant cell only becomes firm. Why does the plant cell not burst?

    • A. Its chloroplasts convert extra water into starch
    • B. Its large vacuole absorbs extra water and shrinks
    • C. Its cell wall resists expansion, so pressure potential rises
    • D. Its membrane is less permeable than a red cell's
  25. Q30. People who take certain sedatives for a long time often show a large increase in smooth ER in liver cells. Which role of the smooth ER accounts for this?

    • A. Packaging of drugs into lysosomes by budding
    • B. Storage of drugs inside peroxisomes
    • C. Synthesis of secretory proteins on bound ribosomes
    • D. Detoxification of drugs by membrane-bound enzymes