NUMS — Medical & Dental Entry Test

NUMS Biology — Biological Molecules and Enzymes (Set 7)

Take the NUMS Biology — Biological Molecules and Enzymes (Set 7): 30 multiple-choice questions (40 minutes) with instant scoring and a full answer review.…

What this test covers

Sample questions with answers

The first 5 questions of this test, with the correct answer and explanation.

  1. Q1. An enzyme follows Michaelis–Menten kinetics with Km = 4 mM and Vmax = 120 µmol/min. At what substrate concentration is the reaction velocity 90 µmol/min?

    • A. 16 mM
    • B. 12 mM ✓
    • C. 6 mM
    • D. 8 mM

    Answer: B. 12 mM

    Explanation: v = Vmax[S]/(Km+[S]); 90 = 120[S]/(4+[S]) gives 90×4 = 30[S], so [S] = 12 mM.

  2. Q2. Chemical analysis of a nucleic acid from a virus gives these base percentages: A 23%, G 32%, C 21%, T 24%. Which description fits the sample best?

    • A. Double-stranded RNA, as its pairing rule is the same as that of DNA
    • B. Double-stranded DNA, as its bases follow the pairing rule A = T and G = C
    • C. Single-stranded RNA, as thymine is found in RNA in place of uracil
    • D. Single-stranded DNA, as its A and T values and its G and C values are not equal ✓

    Answer: D. Single-stranded DNA, as its A and T values and its G and C values are not equal

    Explanation: Thymine marks it as DNA. In a double helix A = T and G = C (Chargaff's rules), but here 23 ≠ 24 and 32 ≠ 21, so the bases are not paired: the DNA is single-stranded.

  3. Q3. In amylopectin an α-1,6 branch point occurs on average once in every 25 glucose residues, and in glycogen once in every 10. About how many branch points would a chain of 1200 glucose residues have in each polymer?

    • A. 25 in amylopectin and 10 in glycogen
    • B. 120 in amylopectin and 48 in glycogen
    • C. 48 in amylopectin and 120 in glycogen ✓
    • D. 48 in amylopectin and 12 in glycogen

    Answer: C. 48 in amylopectin and 120 in glycogen

    Explanation: Branch points = residues ÷ spacing: 1200 ÷ 25 = 48 for amylopectin and 1200 ÷ 10 = 120 for glycogen. Glycogen is the more highly branched.

  4. Q4. A protein is made of four polypeptide chains that together contain 400 amino acid residues. How many peptide bonds does the whole molecule contain? (Assume no other covalent cross-links are counted.)

    • A. 400
    • B. 399
    • C. 396 ✓
    • D. 392

    Answer: C. 396

    Explanation: Each chain of n residues has n−1 peptide bonds, so 400 residues in 4 chains give 400 − 4 = 396.

  5. Q5. Boiling an egg white turns it from clear to opaque white. Which change explains this?

    • A. The amino acid sequence changes, so a new protein is formed from the old
    • B. Hydrogen bonds and weak interactions break, so the protein unfolds and clumps ✓
    • C. Peptide bonds break, so the protein splits into free amino acids
    • D. Disulphide bonds form between all the amino acids, so water is released

    Answer: B. Hydrogen bonds and weak interactions break, so the protein unfolds and clumps

    Explanation: Heat disrupts hydrogen bonds, ionic and hydrophobic interactions. The primary structure with its peptide bonds is not hydrolysed, but the unfolded chains clump together.

The other 25 questions

Take the timed test (free, no sign-up) to see your score and the answer and explanation for every question.

  1. Q6. A double-stranded DNA fragment contains 2000 nucleotides in total, of which 30% are guanine. How many hydrogen bonds hold the two strands together? (A–T pairs have 2, G–C pairs have 3.)

    • A. 2800
    • B. 2200
    • C. 3000
    • D. 2600
  2. Q7. One strand of a DNA duplex has the composition A 20%, G 30%, T 25%, C 25%. What is the percentage of guanine in the whole duplex?

    • A. 30%
    • B. 22.5%
    • C. 25%
    • D. 27.5%
  3. Q8. Analysis of a viral genome gives A 24%, T 36%, G 20%, C 20%. What is the best conclusion?

    • A. The genome is double-stranded DNA with a sequencing error
    • B. The genome is RNA, because it contains four bases
    • C. The genome is single-stranded DNA, because A does not equal T
    • D. The genome is double-stranded DNA, because G equals C
  4. Q9. Four double-stranded DNA samples have the following GC contents. Which melts (strands separate) at the highest temperature?

    • A. Sample with 62% G + C
    • B. Sample with 38% G + C
    • C. Sample with 51% G + C
    • D. Sample with 45% G + C
  5. Q10. A student adds iodine solution to a colourless solution and sees a red-brown colour. After boiling with dilute acid and neutralising, the product gives a brick-red precipitate with Benedict's reagent. The solution most likely contains:

    • A. cellulose, an unbranched β-glucose polymer
    • B. sucrose, a non-reducing disaccharide of glucose and fructose
    • C. glycogen, a highly branched α-glucose polymer
    • D. amylose, a mostly unbranched α-glucose polymer
  6. Q11. A sample gives no colour change with Benedict's reagent. After boiling with dilute HCl and neutralising with sodium hydrogencarbonate, it gives a brick-red precipitate. Which carbohydrate is most likely present?

    • A. A reducing monosaccharide such as fructose
    • B. A non-reducing disaccharide such as sucrose
    • C. A branched polysaccharide such as cellulose
    • D. A reducing disaccharide such as lactose
  7. Q12. Which solution gives a violet colour when treated with dilute copper sulphate in alkaline conditions (Biuret test)?

    • A. Olive oil emulsion
    • B. Glucose solution in water
    • C. Egg albumin solution
    • D. Starch solution in water
  8. Q13. A linear glucan chain contains 1200 glucose residues joined by glycosidic bonds. How many water molecules are released when it is built from free glucose, and how many are needed to hydrolyse it back completely?

    • A. 1200 released and 1200 needed
    • B. 1200 released and 1199 needed
    • C. 1199 released and 1200 needed
    • D. 1199 released and 1199 needed
  9. Q14. A bacterial culture grows well on D-glucose but not on L-glucose, although both have the same formula. The most likely reason is that:

    • A. enzyme active sites are stereospecific and fit only D-glucose
    • B. D-glucose is the only sugar that can dissolve in water
    • C. L-glucose contains a different number of carbon atoms
    • D. L-glucose is too large to enter any bacterial cell
  10. Q15. Triglycerides made entirely of palmitic acid (saturated) and entirely of linoleic acid (two cis double bonds) are compared at 25 °C. Which statement is most likely correct?

    • A. The palmitic triglyceride is liquid because saturated chains pack loosely and move freely
    • B. The linoleic triglyceride is solid because double bonds make the chains straight and rigid
    • C. The linoleic triglyceride is liquid because cis double bonds kink the chains
    • D. Both are solid because both contain three ester bonds
  11. Q16. Collagen contains glycine at about every third position. What is the main reason for this regularity?

    • A. Glycine is the only amino acid that is charged and binds water
    • B. Glycine has the smallest side chain and fits inside the triple helix
    • C. Glycine has a large ring that stabilises the helix by stacking
    • D. Glycine forms disulphide bonds that join the three strands covalently
  12. Q17. Adult haemoglobin contains four polypeptide chains. Which statement about its structure is correct?

    • A. It shows only tertiary structure, being made of one long chain
    • B. It shows quaternary structure, being made of two α and two β chains
    • C. It shows quaternary structure, being made of four identical chains
    • D. It shows only secondary structure, being a single α-helix
  13. Q18. A dialysed enzyme preparation has lost its activity. Adding the boiled dialysate (the small molecules that passed through the membrane) restores the activity, but adding boiled enzyme does not. What can be concluded?

    • A. The enzyme is itself small and heat-stable, so boiling cannot affect it
    • B. The enzyme needs a large heat-labile coenzyme removed by dialysis
    • C. The enzyme was denatured by dialysis and then refolded by the dialysate
    • D. The enzyme needs a small heat-stable coenzyme removed by dialysis
  14. Q19. A dietary deficiency of niacin would most directly reduce the synthesis of which coenzyme?

    • A. FAD, which carries hydrogen in the Krebs cycle only
    • B. ATP, which transfers phosphate in all kinases
    • C. NAD⁺, which carries hydrogen in dehydrogenase reactions
    • D. Coenzyme A, which carries acyl groups in the link reaction
  15. Q20. During glycolysis an enzyme moves a phosphate group from carbon 3 to carbon 2 of the same molecule (3-phosphoglycerate to 2-phosphoglycerate), with no redox change and no other change. Which class does this mutase belong to?

    • A. Ligase
    • B. Hydrolase
    • C. Oxidoreductase
    • D. Isomerase
  16. Q21. A product accumulates in an enzyme assay as follows: 12 µmol at 1 min, 22 µmol at 2 min, 30 µmol at 3 min, 36 µmol at 4 min, 40 µmol at 5 min (0 µmol at 0 min). Which statement about the reaction is correct?

    • A. The initial velocity is 8 µmol/min, because it is the mean rate over 5 min
    • B. The initial velocity is 40 µmol/min, because that is the final amount
    • C. The rate is constant at 12 µmol/min, because the enzyme is saturated
    • D. The initial velocity is 12 µmol/min, and the rate falls as substrate is used up
  17. Q22. The rate of an enzyme-catalysed reaction below its optimum is 5 µmol/min at 15 °C. Assuming a temperature coefficient (Q₁₀) of 2 and no denaturation up to 35 °C, what is the rate at 35 °C?

    • A. 40 µmol/min
    • B. 10 µmol/min
    • C. 15 µmol/min
    • D. 20 µmol/min
  18. Q23. The activity of an enzyme is 20% of maximum at pH 4, 100% at pH 7 and 10% at pH 10. The fall in activity at pH 10 is best explained by:

    • A. a rise in the number of substrate molecules in solution
    • B. conversion of the enzyme into its coenzyme form at high pH
    • C. altered ionisation of amino acid side chains, which distorts the active site
    • D. breakage of the peptide bonds that join the amino acids
  19. Q24. In a reaction with excess substrate, the enzyme concentration is doubled. How do Vmax and Km change?

    • A. Both Vmax and Km double together
    • B. Vmax is unchanged and Km doubles also
    • C. Vmax doubles and Km is unchanged
    • D. Vmax doubles and Km is halved too
  20. Q25. In a metabolic pathway, excess isoleucine (the end product) switches off the first enzyme, threonine deaminase, by binding to a site away from the active site. This is an example of:

    • A. covalent activation of an inactive zymogen
    • B. allosteric feedback inhibition
    • C. irreversible poisoning by heavy metal ions
    • D. competitive inhibition at the active site
  21. Q26. An enzyme is inhibited by a compound that closely resembles its substrate. The inhibition is reduced when the substrate concentration is greatly increased. The inhibitor is acting as:

    • A. a non-competitive inhibitor that binds elsewhere on the enzyme
    • B. an irreversible inhibitor that forms covalent bonds
    • C. a competitive inhibitor that occupies the active site reversibly
    • D. an allosteric activator that stabilises the active form
  22. Q27. Pepsin is secreted as pepsinogen, which becomes active only in the stomach lumen when acid removes part of the chain. What is the main advantage of this arrangement?

    • A. It allows the enzyme to be reused as a coenzyme later
    • B. It raises the optimum pH of the enzyme inside the cell
    • C. It prevents the enzyme from digesting the cells that make it
    • D. It lowers the activation energy of acid secretion itself
  23. Q28. An RNA nucleotide is identified by the presence of which pair of features?

    • A. Uracil as the base and a hydroxyl group on carbon 2 of the sugar
    • B. Thymine as the base and no hydroxyl group on carbon 2 of the sugar
    • C. Thymine as the base and a hydroxyl group on carbon 2 of the sugar
    • D. Uracil as the base and no hydroxyl group on carbon 2 of the sugar
  24. Q29. Insects such as pond skaters walk on the surface of a pond without sinking. Which property of water is mainly responsible?

    • A. Acting as a non-polar solvent for the insect's feet
    • B. Surface tension caused by hydrogen bonding between its molecules
    • C. High density of liquid water compared with solid ice
    • D. Low specific heat capacity caused by weak covalent bonds
  25. Q30. Two enzymes act on the same substrate. Enzyme P reaches half of Vmax at 0.5 mM substrate and enzyme Q at 5 mM. Which statement is correct?

    • A. Enzyme Q has the higher affinity for the substrate, because its Km is higher
    • B. Enzyme P has the higher Vmax, because it reaches half of Vmax sooner
    • C. Both have the same affinity, because Km does not describe binding
    • D. Enzyme P has the higher affinity for the substrate, because its Km is lower