ECAT — Engineering College Admission Test (UET)
Take the ECAT Mathematics — Mathematical Induction and Binomial Theorem (Set 2): 30 multiple-choice questions (40 minutes) with instant scoring and a full…
What this test covers
The first 5 questions of this test, with the correct answer and explanation.
Q1. The coefficient of x⁵ in the expansion of 1/(1 − x)³ (|x| < 1) is:
Answer: D. 21
Explanation: (1 − x)⁻³ = Σ ⁽ʳ⁺²⁾C₂ xʳ, so the coefficient of x⁵ is ⁷C₂ = 21.
Q2. In Pascal's triangle, the middle entry of the row giving the coefficients of (a + b)⁶ is:
Answer: A. 20
Explanation: The row for n = 6 is 1, 6, 15, 20, 15, 6, 1; the middle entry is ⁶C₃ = 20.
Q3. In the binomial series for (1 + x)^(−1/2), what is the coefficient of x²?
Answer: A. 3/8
Explanation: Coefficient = (−1/2)(−3/2)/2! = (3/4)/2 = 3/8.
Q4. To prove 1² + 2² + … + n² = n(n + 1)(2n + 1)/6 by induction, after assuming it for n = k, the term added to both sides is:
Answer: D. (k + 1)²
Explanation: Going from k to k + 1 adds the next term of the series, (k + 1)², to the left-hand side.
Q5. For |x| < 1 and any rational n, the (r + 1)th term of the binomial series (1 + x)ⁿ is:
Answer: B. [n(n − 1)(n − 2)…(n − r + 1)/r!] xʳ
Explanation: The general term of (1 + x)ⁿ is n(n − 1)…(n − r + 1)xʳ/r!, which reduces to ⁿCᵣxʳ when n is a positive integer.
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Q6. The coefficient of x³ in the expansion of (1 + 2x)(1 + x)⁵ is:
Q7. Let P(k) be the statement 2 + 4 + 6 + … + 2k = k(k + 1). Then P(k + 1) is:
Q8. The middle term in the expansion of (2x + 3)⁴ is:
Q9. Find the least positive integer n₀ for which the inequality n! > 2ⁿ is true for all n ≥ n₀.
Q10. The principle of mathematical induction is used to prove statements that are true for all:
Q11. For every positive integer n, the product n(n + 1)(n + 2) is always divisible by:
Q12. Using the binomial expansion up to two terms, √99 is approximately:
Q13. For which values of x does the binomial series of 1/(2 + x) converge?
Q14. Using the binomial theorem, the value of (99)³ is:
Q15. The coefficient of x² in the expansion of (2 + x)⁵ is:
Q16. For every positive integer n, 7ⁿ − 3ⁿ is divisible by:
Q17. When (1 + x)⁵ − (1 − x)⁵ is expanded and simplified, the number of non-zero terms is:
Q18. If the expansion of (a + b)ⁿ has 21 terms, then n equals:
Q19. The remainder when 2³⁰ is divided by 7 is:
Q20. In the expansion of (a − b)¹⁰, the term containing b⁷ is:
Q21. The term independent of x in the expansion of (2x + 1/x²)⁹ is:
Q22. The expansion of (x + y)¹¹ has:
Q23. The term independent of x in the expansion of (x − 2/x)⁶ is:
Q24. The greatest binomial coefficient in the expansion of (1 + x)¹⁰ is:
Q25. When n is a negative integer, the binomial expansion of (1 + x)ⁿ (|x| < 1) has:
Q26. The value of ⁵C₁ + 2·⁵C₂ + 3·⁵C₃ + 4·⁵C₄ + 5·⁵C₅ is:
Q27. The 5th term in the expansion of (x − 2)⁷ is:
Q28. The sum of all the coefficients in the expansion of (3x − 2)⁵ is:
Q29. If the coefficients of the 2nd and 3rd terms in the expansion of (1 + x)ⁿ are in the ratio 1 : 3, then n equals:
Q30. Find the coefficient of x² when (1 − 3x)^(1/3) is expanded in ascending powers of x.