ECAT — Engineering College Admission Test (UET)

ECAT Chemistry — Thermochemistry, Equilibrium and Kinetics (Set 6)

Take the ECAT Chemistry — Thermochemistry, Equilibrium and Kinetics (Set 6): 30 multiple-choice questions (40 minutes) with instant scoring and a full…

What this test covers

Sample questions with answers

The first 5 questions of this test, with the correct answer and explanation.

  1. Q1. CaCO₃(s) ⇌ CaO(s) + CO₂(g) is at equilibrium in a closed cylinder at fixed temperature. The piston is pushed in until the volume is halved, and equilibrium is re-established at the same temperature. Compared with the original, the CO₂ pressure and the mass of CaCO₃ are now:

    • A. pressure unchanged; mass of CaCO₃ greater ✓
    • B. pressure unchanged; mass of CaCO₃ unchanged
    • C. pressure halved; mass of CaCO₃ greater
    • D. pressure doubled; mass of CaCO₃ unchanged

    Answer: A. pressure unchanged; mass of CaCO₃ greater

    Explanation: K_p = p(CO₂) depends only on temperature, so the pressure returns to its original value. Fewer moles of CO₂ are needed at the same pressure in the smaller volume, so CO₂ recombines with CaO, increasing CaCO₃.

  2. Q2. N₂O₄(g) ⇌ 2NO₂(g) is 20% dissociated (α = 0.20) at a total pressure of 1.0 atm. The value of K_p is:

    • A. 0.167 atm ✓
    • B. 0.800 atm
    • C. 0.040 atm
    • D. 0.200 atm

    Answer: A. 0.167 atm

    Explanation: With initial 1 mol: N₂O₄ = 0.8, NO₂ = 0.4, total 1.2 mol. p(NO₂) = 0.333, p(N₂O₄) = 0.667 atm. K_p = (0.333)²/0.667 = 0.167 atm (= 4α²P/(1 − α²)).

  3. Q3. 2.0 mol each of A and B are mixed in a 1.0 dm³ vessel: A + B ⇌ C + D, K_c = 4.0. The equilibrium concentration of C is:

    • A. 0.67 mol dm⁻³
    • B. 1.60 mol dm⁻³
    • C. 1.33 mol dm⁻³ ✓
    • D. 1.00 mol dm⁻³

    Answer: C. 1.33 mol dm⁻³

    Explanation: x²/(2 − x)² = 4, so x/(2 − x) = 2 and x = 4/3 = 1.33 mol dm⁻³.

  4. Q4. The pH of 0.10 M sodium acetate solution (K_a of acetic acid = 1.8 × 10⁻⁵; pK_a = 4.745, pK_w = 14) is:

    • A. 5.13
    • B. 8.87 ✓
    • C. 7.00
    • D. 9.26

    Answer: B. 8.87

    Explanation: CH₃COO⁻ hydrolyses: pH = 7 + ½(pK_a + log C) = 7 + ½(4.745 − 1) = 8.87.

  5. Q5. 100 cm³ of 0.20 M acetic acid (pK_a = 4.74) is mixed with 50 cm³ of 0.20 M NaOH. The pH of the resulting solution is:

    • A. 4.44
    • B. 4.74 ✓
    • C. 2.87
    • D. 7.00

    Answer: B. 4.74

    Explanation: NaOH (10 mmol) converts half of the acid (20 mmol) to acetate, leaving 10 mmol acid and 10 mmol acetate. pH = pK_a + log(1) = 4.74.

The other 25 questions

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  1. Q6. K_sp of Mg(OH)₂ is 1.2 × 10⁻¹¹ at 25 °C. The pH of its saturated solution is:

    • A. 11.46
    • B. 9.46
    • C. 3.54
    • D. 10.46
  2. Q7. Equal volumes of 1.0 × 10⁻⁵ M BaCl₂ and 1.0 × 10⁻⁵ M Na₂SO₄ are mixed (K_sp of BaSO₄ = 1.1 × 10⁻¹⁰). Which statement is correct?

    • A. No precipitate forms, because the ionic product 2.5 × 10⁻¹¹ is below K_sp
    • B. A precipitate forms, because the ionic product 1.0 × 10⁻¹⁰ equals K_sp
    • C. No precipitate forms, because BaSO₄ is soluble
    • D. A precipitate forms, because both ions are present
  3. Q8. The solubility product of PbI₂ is 7.1 × 10⁻⁹. Its solubility in 0.10 M KI (taking [I⁻] = 0.10 M) is:

    • A. 7.1 × 10⁻⁷ M
    • B. 1.2 × 10⁻³ M
    • C. 7.1 × 10⁻⁸ M
    • D. 1.8 × 10⁻⁷ M
  4. Q9. Initial rates for A + B → products: (i) [A] = 0.10, [B] = 0.10 M, rate = 2.0 × 10⁻³ M s⁻¹; (ii) [A] = 0.20, [B] = 0.10, rate = 8.0 × 10⁻³; (iii) [A] = 0.10, [B] = 0.30, rate = 6.0 × 10⁻³. The rate constant k is:

    • A. 2.0 dm⁶ mol⁻² s⁻¹
    • B. 0.20 dm⁶ mol⁻² s⁻¹
    • C. 20 dm⁶ mol⁻² s⁻¹
    • D. 2.0 dm³ mol⁻¹ s⁻¹
  5. Q10. A first-order reaction has k = 5.0 × 10⁻³ s⁻¹. The time taken for the concentration to fall from 0.80 M to 0.10 M is about (ln 2 = 0.693):

    • A. 416 s
    • B. 1386 s
    • C. 139 s
    • D. 277 s
  6. Q11. For a second-order reaction 2A → products with rate constant k = 0.050 dm³ mol⁻¹ s⁻¹, the half-life when the initial concentration is 0.80 M (t½ = 1/(k[A]₀)) is:

    • A. 14 s
    • B. 50 s
    • C. 25 s
    • D. 12.5 s
  7. Q12. For a reaction with activation energy 50 kJ mol⁻¹, by what factor does the rate constant increase when the temperature is raised from 300 K to 310 K (R = 8.314 J K⁻¹ mol⁻¹; ln k₂/k₁ = (Eₐ/R)(1/T₁ − 1/T₂))?

    • A. 2.0
    • B. 1.9
    • C. 3.8
    • D. 1.2
  8. Q13. An exothermic reaction has ΔH = −40 kJ mol⁻¹ and a forward activation energy of 80 kJ mol⁻¹. A catalyst lowers the forward activation energy to 60 kJ mol⁻¹. The activation energy of the reverse reaction with the catalyst is:

    • A. 100 kJ mol⁻¹
    • B. 120 kJ mol⁻¹
    • C. 20 kJ mol⁻¹
    • D. 40 kJ mol⁻¹
  9. Q14. CH₄(g) + 2O₂(g) → CO₂(g) + 2H₂O(l) has ΔH = −890 kJ mol⁻¹ at 298 K. Taking R = 8.314 J K⁻¹ mol⁻¹, ΔU is (ΔH = ΔU + ΔnRT):

    • A. −895.0 kJ mol⁻¹
    • B. −885.0 kJ mol⁻¹
    • C. −877.6 kJ mol⁻¹
    • D. −890.0 kJ mol⁻¹
  10. Q15. ΔH_comb (kJ mol⁻¹): C(graphite) −393.5, H₂(g) −285.8, C₃H₈(g) −2220.0. The standard enthalpy of formation of propane (3C + 4H₂ → C₃H₈) is:

    • A. −1 180.5 kJ mol⁻¹
    • B. −2899.7 kJ mol⁻¹
    • C. −103.7 kJ mol⁻¹
    • D. +103.7 kJ mol⁻¹
  11. Q16. 4.0 g of NaOH (0.10 mol) dissolves in 200 g of water and the temperature rises by 5.0 °C. Taking the specific heat of the solution as 4.18 J g⁻¹ K⁻¹ and using a mass of 200 g, the enthalpy of solution of NaOH is:

    • A. +41.8 kJ mol⁻¹
    • B. −41.8 kJ mol⁻¹
    • C. −418 kJ mol⁻¹
    • D. −4.18 kJ mol⁻¹
  12. Q17. Standard enthalpies of combustion are: C(graphite) −394, H₂(g) −286 and CH₄(g) −890 kJ mol⁻¹. The enthalpy of formation of CH₄(g) from its elements is:

    • A. −76 kJ mol⁻¹
    • B. −1856 kJ mol⁻¹
    • C. −966 kJ mol⁻¹
    • D. +76 kJ mol⁻¹
  13. Q18. 100 cm³ of 1.00 M HCl is mixed with 100 cm³ of 1.00 M NaOH in an insulated cup and the temperature rises by 6.5 °C. Taking the mixture as 200 g of solution with specific heat 4.2 J g⁻¹ K⁻¹, the molar enthalpy of neutralisation is:

    • A. −54.6 kJ mol⁻¹
    • B. −27.3 kJ mol⁻¹
    • C. −5.46 kJ mol⁻¹
    • D. −109 kJ mol⁻¹
  14. Q19. For N₂ + 3H₂ ⇌ 2NH₃ at a certain temperature K_c = 40 (dm⁶ mol⁻²). A mixture has [N₂] = 0.10, [H₂] = 0.20 and [NH₃] = 0.20 mol dm⁻³. The reaction will proceed:

    • A. in the forward direction, since Q = 0.5 is below K_c
    • B. in the forward direction, since Q = 50 exceeds K_c
    • C. in the reverse direction, since Q = 50 exceeds K_c
    • D. in neither direction, since the system is at equilibrium
  15. Q20. N₂(g) + 3H₂(g) ⇌ 2NH₃(g) is at equilibrium in a flexible container kept at constant total pressure and temperature. Helium is added, so the volume increases. The equilibrium:

    • A. does not shift, because He is inert
    • B. shifts towards the reactants
    • C. shifts towards NH₃ since the total moles increase
    • D. shifts towards the product, NH₃
  16. Q21. In which of these changes does the entropy of the system decrease?

    • A. NH₄Cl(s) → NH₃(g) + HCl(g)
    • B. 2NO(g) + O₂(g) → 2NO₂(g)
    • C. CaCO₃(s) → CaO(s) + CO₂(g)
    • D. N₂O₄(g) → 2NO₂(g)
  17. Q22. 100 cm³ of 0.10 M HCl is mixed with 100 cm³ of 0.050 M NaOH. The pH of the mixture is:

    • A. 7.00
    • B. 1.00
    • C. 1.60
    • D. 1.30
  18. Q23. The pH of 1.0 × 10⁻⁷ M HCl at 25 °C, allowing for the ionisation of water (K_w = 1.0 × 10⁻¹⁴), is:

    • A. 6.50
    • B. 6.79
    • C. 7.30
    • D. 7.00
  19. Q24. The pH of 0.10 M NH₄Cl solution (K_b of NH₃ = 1.8 × 10⁻⁵, pK_b = 4.745, pK_w = 14) is:

    • A. 5.13
    • B. 4.13
    • C. 8.87
    • D. 11.13
  20. Q25. The reaction NO₂ + CO → NO + CO₂ has the experimental rate law rate = k[NO₂]². Which mechanism is consistent with it?

    • A. Fast step: 2NO₂ → NO₃ + NO; slow step: NO₃ + CO → NO₂ + CO₂
    • B. Slow step: NO₂ + CO → NO + CO₂ in one step
    • C. Slow step: 2NO₂ → NO₃ + NO; fast step: NO₃ + CO → NO₂ + CO₂
    • D. Slow step: CO → C + O; fast step: C + NO₂ → NO + CO
  21. Q26. The rate of a reaction is proportional to [A]^(3/2). The units of its rate constant (concentration in mol dm⁻³, time in s) are:

    • A. mol^(1/2) dm^(−3/2) s⁻¹
    • B. mol^(3/2) dm^(−3/2) s⁻¹
    • C. mol⁻¹ dm³ s⁻¹
    • D. mol^(−1/2) dm^(3/2) s⁻¹
  22. Q27. For 2N₂O₅ → 4NO₂ + O₂, the rate of formation of NO₂ is 4.0 × 10⁻³ mol dm⁻³ s⁻¹. Taking the rate of reaction as defined by rate = −½d[N₂O₅]/dt, the rate of formation of O₂ is:

    • A. 4.0 × 10⁻³ mol dm⁻³ s⁻¹
    • B. 2.0 × 10⁻³ mol dm⁻³ s⁻¹
    • C. 8.0 × 10⁻³ mol dm⁻³ s⁻¹
    • D. 1.0 × 10⁻³ mol dm⁻³ s⁻¹
  23. Q28. In a first-order decomposition of H₂O₂, 20% of the initial amount decomposes in the first 10 minutes. The percentage of the initial amount remaining after 30 minutes is:

    • A. 48.8%
    • B. 40.0%
    • C. 60.0%
    • D. 51.2%
  24. Q29. For the equilibrium 2A ⇌ B, K_c = 4.0 (concentrations in mol dm⁻³). For A ⇌ ½B at the same temperature, K_c is:

    • A. 8.0
    • B. 0.50
    • C. 0.25
    • D. 2.0
  25. Q30. How much heat is needed to raise the temperature of 2.0 mol of a monatomic ideal gas by 10 K at constant pressure (C_p = 5R/2, R = 8.314 J K⁻¹ mol⁻¹)?

    • A. 332 J
    • B. 416 J
    • C. 166 J
    • D. 249 J