ECAT — Engineering College Admission Test (UET)

ECAT Chemistry — Chemical Bonding (Set 3)

Take the ECAT Chemistry — Chemical Bonding (Set 3): 30 multiple-choice questions (40 minutes) with instant scoring and a full answer review. Covers 30…

What this test covers

Sample questions with answers

The first 5 questions of this test, with the correct answer and explanation.

  1. Q1. The shape of the SF₄ molecule is:

    • A. see-saw ✓
    • B. trigonal bipyramidal
    • C. square planar
    • D. tetrahedral

    Answer: A. see-saw

    Explanation: S has 4 bond pairs + 1 lone pair (sp³d); the lone pair sits equatorially, giving a see-saw shape.

  2. Q2. XeF₄ has how many lone pairs on the central atom and what shape?

    • A. 1 lone pair; see-saw
    • B. 2 lone pairs; tetrahedral
    • C. 2 lone pairs; square planar ✓
    • D. 0 lone pairs; square planar

    Answer: C. 2 lone pairs; square planar

    Explanation: Xe has 8 valence electrons: 4 used in bonds, 4 left as 2 lone pairs; the pairs sit axially, giving a square-planar molecule (sp³d²).

  3. Q3. The shape of the ClF₃ molecule is:

    • A. trigonal planar
    • B. linear
    • C. T-shaped ✓
    • D. trigonal pyramidal

    Answer: C. T-shaped

    Explanation: Cl: 3 bond pairs + 2 lone pairs (sp³d); the lone pairs occupy equatorial positions, leaving a T-shape.

  4. Q4. The ion ICl₂⁻ is linear. The reason is that the central iodine has:

    • A. one lone pair and sp² hybridisation
    • B. two lone pairs and sp³ hybridisation, giving a tetrahedral shape
    • C. three lone pairs in the equatorial plane of a trigonal bipyramid ✓
    • D. no lone pairs and sp hybridisation

    Answer: C. three lone pairs in the equatorial plane of a trigonal bipyramid

    Explanation: I has 7 + 1 = 8 electrons from outside: 2 bond pairs and 3 lone pairs (sp³d); lone pairs sit equatorially, leaving the two Cl atoms axial and 180° apart.

  5. Q5. Which of the following has the smallest bond angle?

    • A. NH₃
    • B. CH₄
    • C. H₂S ✓
    • D. H₂O

    Answer: C. H₂S

    Explanation: H₂S ≈ 92°, H₂O ≈ 104.5°, NH₃ ≈ 107°, CH₄ 109.5°; larger central atom with less electronegativity gives pure p bonding.

The other 25 questions

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  1. Q6. The bond angle in NF₃ (about 102°) is smaller than in NH₃ (about 107°) because:

    • A. NF₃ has no lone pair on nitrogen
    • B. fluorine atoms are smaller than hydrogen atoms
    • C. fluorine draws bonding electrons away from N, so bond pairs repel less
    • D. nitrogen in NF₃ is sp² hybridised
  2. Q7. In the ion NH₄⁺ the nitrogen atom is hybridised as:

    • A. sp³ with four equivalent bonds, one of which is coordinate
    • B. sp³d with four bonds
    • C. sp² with three bonds and a lone pair
    • D. sp with four bonds
  3. Q8. The hybridisation of the carbon atoms in graphite and the C–C–C bond angle in a layer are:

    • A. sp³ and 109.5°
    • B. sp² and 120°
    • C. sp² and 109.5°
    • D. sp and 180°
  4. Q9. The number of σ and π bonds in acetonitrile, CH₃–C≡N, is respectively:

    • A. 5 and 2
    • B. 5 and 3
    • C. 4 and 3
    • D. 6 and 1
  5. Q10. In the molecule CH₂=CH–C≡N, the hybridisations of the three carbon atoms from left to right are:

    • A. sp³, sp², sp
    • B. sp², sp, sp
    • C. sp², sp², sp²
    • D. sp², sp², sp
  6. Q11. Using molecular orbital theory, the bond order of the O₂⁺ ion is:

    • A. 1.5
    • B. 3
    • C. 2.5
    • D. 2
  7. Q12. Which of the following species is paramagnetic?

    • A. C₂
    • B. B₂
    • C. N₂
    • D. F₂
  8. Q13. The order of bond lengths for the species O₂, O₂⁺ and O₂⁻ is:

    • A. O₂⁻ < O₂ < O₂⁺
    • B. O₂⁺ < O₂⁻ < O₂
    • C. O₂ < O₂⁺ < O₂⁻
    • D. O₂⁺ < O₂ < O₂⁻
  9. Q14. The resonance hybrid of the carbonate ion (CO₃²⁻) has each C–O bond order equal to:

    • A. 2
    • B. 1⅓
    • C. 1
    • D. 1½
  10. Q15. In the ozone molecule the two O–O bonds are equal in length because:

    • A. both bonds are triple bonds
    • B. of hydrogen bonding
    • C. ozone has sp³ hybridisation at every oxygen
    • D. of resonance between two structures
  11. Q16. The formal charge on the central sulphur atom in the structure of SO₂ drawn as O=S=O with one lone pair on S is (S has 6 valence electrons):

    • A. +1
    • B. 0
    • C. +2
    • D. −1
  12. Q17. Which of these molecules is non-polar despite having polar bonds?

    • A. BF₃
    • B. CHCl₃
    • C. SO₂
    • D. NH₃
  13. Q18. Of the isomers of dichlorobenzene (C₆H₄Cl₂), the one with zero dipole moment is:

    • A. chlorobenzene
    • B. 1,2-dichlorobenzene
    • C. 1,3-dichlorobenzene
    • D. 1,4-dichlorobenzene
  14. Q19. According to Fajans' rules, which compound has the greatest covalent character?

    • A. CaCl₂
    • B. MgCl₂
    • C. AlCl₃
    • D. NaCl
  15. Q20. The lattice energy order for NaF, MgO and NaCl is expected to be:

    • A. MgO > NaF > NaCl
    • B. MgO > NaCl > NaF
    • C. NaCl > NaF > MgO
    • D. NaF > MgO > NaCl
  16. Q21. Which of the following ionic solids has the highest melting point?

    • A. MgO
    • B. CsI
    • C. KBr
    • D. NaCl
  17. Q22. Percentage ionic character of a bond depends mainly on:

    • A. the bond length alone
    • B. the electronegativity difference between the bonded atoms
    • C. the number of bonds between them
    • D. the atomic masses of the two atoms
  18. Q23. In the coordinate covalent bond formed when BF₃ reacts with NH₃, the electron pair is donated by:

    • A. B of BF₃ to the H of NH₃
    • B. both B and N equally
    • C. F of BF₃ to N
    • D. N of NH₃ into the empty p orbital of B
  19. Q24. The O–N–O bond angles in NO₂⁺, NO₂ and NO₂⁻ follow the order:

    • A. NO₂⁺ > NO₂ > NO₂⁻
    • B. NO₂ > NO₂⁺ > NO₂⁻
    • C. NO₂⁻ > NO₂ > NO₂⁺
    • D. NO₂⁺ > NO₂⁻ > NO₂
  20. Q25. Metallic bonding is best described as:

    • A. dipole–dipole attraction between atoms
    • B. transfer of electrons to form oppositely charged ions
    • C. attraction between positive metal ions and a sea of delocalised electrons
    • D. sharing of electron pairs between two atoms
  21. Q26. Which of the following species has a bond order of 3?

    • A. F₂
    • B. O₂
    • C. B₂
    • D. CO
  22. Q27. Which of the following hydrogen halides has the highest boiling point owing to hydrogen bonding?

    • A. HCl
    • B. HF
    • C. HBr
    • D. HI
  23. Q28. The molecule with the highest bond dissociation energy among the following is:

    • A. O₂
    • B. N₂
    • C. H₂
    • D. F₂
  24. Q29. XeF₂ is a linear molecule. The number of lone pairs on the central xenon atom is:

    • A. 1
    • B. 3
    • C. 0
    • D. 2
  25. Q30. SnCl₄ is a volatile liquid whereas SnCl₂ is a crystalline solid. This difference is best explained by:

    • A. the lower atomic mass of SnCl₄
    • B. a smaller number of Sn–Cl bonds in SnCl₄
    • C. the higher charge on Sn⁴⁺ polarising Cl⁻ and giving covalent character
    • D. hydrogen bonding in SnCl₂